A ball with a mass of #80 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #16 (kg)/s^2# and was compressed by #1/5 m# when the ball was released. How high will the ball go?

1 Answer
Jan 8, 2017

Answer:

I tried this but check my maths.

Explanation:

We can consider:
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So basically we can write:
#1/2kx^2=1/2mv^2#
#v=sqrt((kx^2)/m)=sqrt(8)=2.8m/s#

We now use the kinematic relationship:
#v_f^2=v_i^2+2ah#
With #a=# acceleration of gravity downwards and #v_f=0# for the final velocity;
#0=8-(2*9.8*h)#
#h=8/(2*9.8)=0.4m#
If we consider also the initial compression, the total vertical distance should be:
#h+h_1=0.4+0.2=0.6m#