# A balloon is inflated with 0.2494 g of helium to a pressure of 1.26 atm. If the desired volume of the balloon is 1.250 L, what must the temperature be in °C?

Jun 4, 2016

Approx. $305 - 310 \cdot K$

#### Explanation:

We use the Ideal Gas equation and solve for $\text{Temperature}$:

$T = \frac{P V}{n R}$ $=$

$\frac{1.26 \cdot a t m \times 1.250 \cdot L}{\frac{0.2494 \cdot g}{4.003 \cdot g \cdot m o {l}^{-} 1} \times 0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1}$ $=$ ??K

We get an answer in $\text{Kelvin}$. We must convert this to $\text{Centigrade}$.

$\text{Centigrade Temperature}$ $=$ ("Kelvin Temperature"-"273.15")""^@C