Question

A block of silver has a length of 0.93 m, a width of 60 mm and a height of 12 cm. How do you find the total resistance of the block if it is placed in a circuit such that the current runs along its length? Along its height? Along its width?

Answer 1

for alongside length:
`R_l=0,73935*10^(-8) Omega`
for alongside width:
`R_w=0,012243*10^(-8) Omega`
for alongside height:
`R_h=2,9574*10^(-8) Omega`

Explanation:

`"formula required:"`
`R= rho *l/s`
`rho=1,59*10^-8`
`R= rho *(0,93)/(0,12*0,06)= rho*0,465`
`"for alongside length"`
`R=1,59*10^-8*0,465=0,73935*10^(-8) Omega`

`R= rho *(0,06)/(0,93*0,12)= rho*0,0077`
`"for alongside width"`
`R= 1,59*10^(-8)*0,0077=0,012243*10^(-8) Omega`

`R= rho *(0,12)/(0,06*0,93)= rho*1,86`
`" for alongside height"`
`R=1,59*10^(-8)*1,86=2,9574*10^(-8) Omega`