Question

A Bullet is fired into the air at an angle of `45^circ`. How far does it travel before it is 1,000 feet above the ground?

Answer 1

1414.2136 feet (if the bullet starts it is journey from ground zero)

Explanation:

Since the elevation of the bullet reaches 1000 ft after travelling some time, you need to find hypotenuse of the triangle (1000 ft on one side, 1000 ft on the other side) since this triangle has one 90 degrees and two 45 degrees. (one side is 1000 feet).

The distance: `x=sqrt2*side`

side is 1000 feet.

Therefore,

`x=sqrt2*1000`

`x=1414.2136` feet.