A bullet of mass 2 Kg is having a charge of 2mc. Through what potential difference must it be accelerated, starting from rest, to aquire a speed of 10m/s?

1 Answer
Junaid Mirza
Mar 16, 2018

#"50 kV"#

Explanation:

Energy due to electric field is

#"U" = "q" Δ"V"#

Energy acquired by bullet is kinetic energy. It’s given by

#"K" = 1/2\ "mv"^2#

According to law of conservation of energy

#"U = K"#

#"q"Delta"V" = 1/2\ "mv"^2#

#Δ"V" = "mv"^2/"2q" = "2 kg × (10 m/s)"^2/(2 × 2 × 10^-3\ "C") = 5 × 10^4\ "Volt" = "50 kV"#

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