Question

A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance 120 meters. What is the approximate acceleration of the car?

Answer 1

`6.01 m/s^2`

Explanation:

for the motion's law you know:
`s= v° xx t + 1/2 a t^2`
but v° ( initially v) is zero so
`a= (2 s)/t^2= (2 xx 120 m)/ (6.32s)^2= 6.01 m/s^2`