A cart with an initial velocity of # 5.0# #m##/s# to the right experiences a constant acceleration of #2.0# #m##/s^2# to the right. What is the cart's displacement during the first #6.0# #s# of this motion?

1 Answer
Jul 23, 2017

#66# metres to the right.

Explanation:

We start by noting that all the motion given is moving to the right, or in the positive direction. This means that our final answer for displacement will be positive as well.

We can use the equation #s = v_0t + 1/2at^2#.

#s = (5.0 m/s)(6.0s) + 1/2(2.0m/s^2)(6.0s)^2#

#s = 30.0 + 36.0 m#

#s = 66 m#

This means #66# metres to the right will be the displacement.

Hopefully this helps!