# A certain mass of #CaC_2# reacts completely with water to give 64.5 L of #C_2H_2# at 50.0 C and 1.00 atm. If the same mass of #CaC_2# reacts completely at 400.0 C and P = 1.00 atm, what volume of #C_2H_2# will be collected at the higher temperature?

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Calcium carbide (#CaC_2# ) reacts with water to produce acetylene (#C_2H_2# ) according to the equation

#CaC_2 + 2H_2O -> Ca(OH)_2 + C_2H_2#

Calcium carbide (

##### 1 Answer

#### Answer:

The volume of acetylene is 134 L.

#### Explanation:

This is really a disguised **Charles' Law** problem.

In each case, we have the same mass and therefore the same number of moles of calcium carbide.

Hence, we will have the same number of moles of acetylene in each case.

Thus,

Charles' Law is

#color(blue)(bar(ul(|color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)|)))" "#

We can rearrange this to get

#V_2 = V_1 × T_2/T_1#

In this problem,

∴