A charge of #1 C# is at #(3,-2)# and a charge of #-3 C# is at #( 7,-1) #. If both coordinates are in meters, what is the force between the charges?

1 Answer
Mar 13, 2016

Answer:

#F=-1,59*10^9" "N#

Explanation:

#F="force between two charges"#
#q_1,q_2:"charges"#
#d:"distance between two charges"#
#"The force between two charges is determined by :"#
#F=k(q_1*q_2)/d^2#
#"let's calculate distance between two charges"#
#P_1=(3,-2)#
#P_2=(7,-1)#
#Delta x=P_"2x"-P_"1x"=7-3=4#
#Delta y=P_"2y"-P_"1y"=-1+2=1#
#d=sqrt(Delta x^2+Delta y^2)" "d=sqrt(4^2+1^2)" "d=sqrt17#
#F=k(1*(-3))/(sqrt17)^2#
#F=(-3k)/17" "k=9*10^9 N*m^2*C^-2#
#F=(-3*9*10^9)/17#
#F=-(27*10^9)/17#
#F=-1,59*10^9" "N#