A charge of 16C is passing through points A and B on a circuit. If the charge's electric potential changes from 24J to 3J, what is the voltage between points A and B?

1 Answer
Feb 25, 2017

V=338

Explanation:

The equation that

U=(12)QV2

We're given U=3 and 24. We're also given that Q=16 Plug in for both situations.

24=(12)(16)(V)2

Solve for V:

V=3

Now repeat for the other one:

3=(12)(16)(V)2

V=38

The voltage in between these points is the change in voltage:

V=338