A charge of #16 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #27 J# to #3 J#, what is the voltage between points A and B?

1 Answer
Dec 16, 2016

Answer:

A and B differ by 1.5 volts.

Explanation:

The relation you need is essentially the definition of voltage (electric potential):

W = qV

where W is the change in electric potential energy, q is the quantity of charge transported and V is the potential difference (or voltage difference) between the two points.

(Incidentally, your question should read:
A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential energy changes from 27 J to 3 J, what is the voltage between points A and B?)

Anyway, here we go:

24 J = 16 C x V

V = #24/16# #J/C#= 1.5 volts

(Note: The unit volt is identical to the combined units joules per coulomb)