# A charge of 18 C passes through a circuit every 24 s. If the circuit can generate 4 W of power, what is the circuit's resistance?

calculation of current strength I = $\frac{Q}{t} = \frac{18}{24} A$
Now Power (P) =${I}^{2} \cdot R$
hence $R = \frac{p}{I} ^ 2 = 4 \cdot {24}^{2} / {18}^{2}$ ohm=7.11 ohm