A charge of $2 C$ $2 C$ is at $(- 2, 4)$ $(-2 , 4 )$ and a charge of $- 1 C$ $-1 C$ is at $(- 6, 8)$ $(-6 ,8 )$ . If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2018-05-24T08:42:35

$5.62 \cdot 10^{8} N$ $5.62*10^8"N"$

$F = \frac{k Q_{1} Q_{2}}{r^{2}}$ $F=(kQ_1Q_2)/r^2$ , where:

$F$ $F$ = electrostatic force ( $N$ $"N"$ )
$k$ $k$ = Coulomb's constant ( $~ 8.99 \cdot 10^{9} {N C}^{2} m^{- 2}$ $~8.99*10^9"N C"^2"m"^-2$ )
$Q_{1} & Q_{2}$ $Q_1 & Q_2$ = charges on points 1 and 2 ( $C$ $"C"$ )
$r$ $r$ = distance between centers of charges ( $m$ $"m"$ )

$r^2=(Deltax)^2+(Deltay)^2=(8-4)^2+(-6+2)^2=4^2+4^2=32$

$F=(2(8.99*10^9))/32=(8.99*10^9)/16=5.62*10^8"N"$

A charge of 2 C2C2 C is at (-2 , 4 )(−2,4)(-2 , 4 ) and a charge of -1 C−1C-1 C is at (-6 ,8 ) (−6,8)(-6 ,8 ) . If both coordinates are in meters, what is the force between the charges?