A charge of #2 C# is at #(-3 ,7)# and a charge of #3 C# is at #( -3 ,5 )#. If both coordinates are in meters, what is the force between the charges?

1 Answer
Feb 17, 2016

Answer:

Force between charges is #1.35⋅10^10# Newton

Explanation:

As the charges (2C and 3C) are at (−3,7) and at (−3,5) respectively, distance between the two is 2 meters (#x# coordinate being same, it is difference in #y# coordinates).

The force between two charges #C_1# and #C_2# is given by #k*(C_1*C_2)/d^2#, where #k# is Coulomb's law constant for the medium between the charges and for air it is #9*10^9 Nm^2/C^2#, where charge is in Coulomb and distance in meters.

As such Force will be given by

#(9*2*3)/(2^2)*10^9# or #13.5*10^9# or #1.35*10^10# Newton.