# A charge of 2 C is at (-3 ,7) and a charge of 3 C is at ( -3 ,5 ). If both coordinates are in meters, what is the force between the charges?

Feb 17, 2016

Force between charges is 1.35⋅10^10 Newton

#### Explanation:

As the charges (2C and 3C) are at (−3,7) and at (−3,5) respectively, distance between the two is 2 meters ($x$ coordinate being same, it is difference in $y$ coordinates).

The force between two charges ${C}_{1}$ and ${C}_{2}$ is given by $k \cdot \frac{{C}_{1} \cdot {C}_{2}}{d} ^ 2$, where $k$ is Coulomb's law constant for the medium between the charges and for air it is $9 \cdot {10}^{9} N {m}^{2} / {C}^{2}$, where charge is in Coulomb and distance in meters.

As such Force will be given by

$\frac{9 \cdot 2 \cdot 3}{{2}^{2}} \cdot {10}^{9}$ or $13.5 \cdot {10}^{9}$ or $1.35 \cdot {10}^{10}$ Newton.