# A charge of -2 C is at (4, -5) and a charge of 1 C is at (-3 , 4 ) . If both coordinates are in meters, what is the force between the charges?

Force $F = 138 , 307 , 692.3 \text{ }$Newtons

#### Explanation:

The formula for Coulomb's Law

$F = {k}_{e} \frac{\left\mid {q}_{1} \cdot {q}_{2} \right\mid}{r} ^ 2 \text{ }$where k_e=8.99 x 10^9" "$N \cdot {m}^{2} \cdot {C}^{- 2}$

$F = {k}_{e} \frac{\left\mid {q}_{1} \cdot {q}_{2} \right\mid}{r} ^ 2 \text{ }$

$F = \left(8.99 x {10}^{9}\right) \cdot \frac{\left\mid \left(- 2\right) \left(1\right) \right\mid}{\sqrt{{\left(4 - - 3\right)}^{2} + {\left(- 5 - 4\right)}^{2}}} ^ 2$

$F = \frac{\left(8.99 x {10}^{9}\right) \cdot 2}{\sqrt{{\left(7\right)}^{2} + {\left(- 9\right)}^{2}}} ^ 2$

F=((8.99 x 10^9)*2)/(sqrt((49+81))^2

$F = \frac{\left(8.99 x {10}^{9}\right) \cdot 2}{130}$

Force $F = 138 , 307 , 692.3 \text{ }$Newtons

God bless......I hope the explanation is useful.