A charge of #-2 C# is at the origin. How much energy would be applied to or released from a # 4 C# charge if it is moved from # (7 ,5 ) # to #(9 ,-2 ) #?

1 Answer
Feb 11, 2016

Answer:

#W=0,062 J#

Explanation:

#V=k*q/d" voltage of any charge on the any point "#
#V_A=k*q_1/sqrt 74 " potential of charge of -2C on the point(7,5)"#
#V_B=k*q_1/sqrt 85" potential of charge of -2C on the point(9,-2)"#
#V_(AB)=V_B-V_A#
#V_(AB)=k*q(1/sqrt 85-1/sqrt 74)#
#V_(AB)=k*q(sqrt 74-sqrt 85)/sqrt (74*85)#
#W=q*V_(AB)#
# "energy required for charge of 4C to move from(7,5) to (9,-2)"#
#W=4*k*q(sqrt 74-sqrt 85)/sqrt (74*85)#
#W=4*(-2)(sqrt 74-sqrt 85)/sqrt (74*85)#*
#W=-8*(8,602-9,219)/(79,31)#
#W=0,062 J#