A charge of $3 C$ $3 C$ passes through a circuit every $9 s$ $9 s$ . If the circuit can generate $6 W$ $6 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-02-27T17:51:51

$54 Omega$

From definition, electric current is the rate of flow of electric charge, that is, $I=Q/t$ .
So in this case, $I=3/9=1/3 A$ .

From the formulae for electric power, we have that $P=I^2R$ .

$therefore R=P/I^2=6/(1/3)^2 =54 Omega$ .

A charge of 3 C3C3 C passes through a circuit every 9 s9s9 s. If the circuit can generate 6 W6W6 W of power, what is the circuit's resistance?