Question

A charge of `3 C` passes through a circuit every `9 s`. If the circuit can generate `6 W` of power, what is the circuit's resistance?

Answer 1

`54 Omega`

Explanation:

From definition, electric current is the rate of flow of electric charge, that is, `I=Q/t`.
So in this case, `I=3/9=1/3 A`.

From the formulae for electric power, we have that `P=I^2R`.

`therefore R=P/I^2=6/(1/3)^2 =54 Omega`.