Question

A charge of `40 C` passes through a circuit every `8 s`. If the circuit can generate `12 W` of power, what is the circuit's resistance?

Answer 1

I found: `0.48Omega`

Explanation:

You can use your data to evaluate current as the rate of flow of charge in time to get:
`I=Q/t=40/8=5A`
We the use the definition of electrical power `P=V*I` and Ohm's Law, `V=R*I`, to get:
`P=I^2*R`
And
`12=5^2*R`
`R=12/25=0.48Omega`