# A charge of 45 C passes through a circuit every 6 s. If the circuit can generate 98 W of power, what is the circuit's resistance?

The resistance is 1.742 $\Omega$
The current in the circuit is the amount of charge that passes by a point per second. It is found from the equation $I = \frac{\Delta Q}{\Delta t} = \frac{45 C}{6 s} = 7.5 A$.
The power in a circuit is found from the equation $P = I V = {I}^{2} R$. This means that the resistance is $R = \frac{P}{{I}^{2}} = \frac{98 W}{7.5 A} ^ 2 = 1.742 \Omega$