# A charge of -5 C is at (1, 3 ) and a charge of 1 C is at (-3 , 4 ) . If both coordinates are in meters, what is the force between the charges?

Jan 29, 2017

Force of attraction is $2.647 \times {10}^{9}$ Newtons

#### Explanation:

As the charges are in opposite direction, the force is that of attraction between the two.

Force is given by $\frac{k \times {Q}_{1} \times {Q}_{2}}{d} ^ 2$, where $k = 9.0 \times {10}^{9}$ $N {m}^{2} / {C}^{2}$

As ${Q}_{1} = - 5 C$ and ${Q}_{2} = 1 C$

and ${d}^{2} = {\left(- 3 - 1\right)}^{2} + {\left(4 - 3\right)}^{2} = 16 + 1 = 17$

Hence, Force is $\frac{9.0 \times {10}^{9} \times 1 \times 5}{17} = 2.647 \times {10}^{9}$ Newtons