# A charge of 5 C is at (9 , 3 ) and a charge of -1 C is at (-2 , 4 ) . If both coordinates are in meters, what is the force between the charges?

Feb 14, 2016

#### Answer:

$F \cong - 0 , 369 \cdot {10}^{9} N$

#### Explanation:

$\text{distance between (9,3) and (-2,4):}$
r²=(-2-9)^2+(4-3)^2
${r}^{2} = {\left(- 11\right)}^{2} + {1}^{2}$
${r}^{2} = 121 + 1$
${r}^{2} = 122$
$\text{Force between two charges is defined as Coulomb's law}$
$F = \frac{k \cdot {q}_{1} \cdot {q}_{2}}{r} ^ 2$
$F = \frac{k \cdot 5 \cdot \left(- 1\right)}{122}$
$F = \frac{- 5 \cdot k}{122}$
$F = \frac{- 5 \cdot 9 \cdot {10}^{9}}{122}$
$F \cong - 0 , 369 \cdot {10}^{9} N$