# A charge of 54 C passes through a circuit every 6 s. If the circuit can generate 63 W of power, what is the circuit's resistance?

May 10, 2016

I found $0.66 \Omega$

#### Explanation:

You know that current $I$ is:
$I = \frac{q}{t} = \frac{54}{6} = 9 A$
We can now use the fact that power is:
$P = V I = {I}^{2} R$
Rearranging:
$R = \frac{P}{I} ^ 2 = \frac{63}{9} ^ 2 = 0.66 \Omega$