# A circle has a center at (3 ,1 ) and passes through (2 ,1 ). What is the length of an arc covering pi/8 radians on the circle?

length of arc $s = r \cdot \theta = 1 \cdot \frac{\pi}{8} = \frac{\pi}{8} = 0.392699$

#### Explanation:

From the given data:
A circle has a center at (3,1) and passes through (2,1). What is the length of an arc covering π/8 radians on the circle?

We need the radius r to compute for the arc

$r = \sqrt{{\left(3 - 2\right)}^{2} + {\left(1 - 1\right)}^{2}} = \sqrt{1} = 1$

$s = r \cdot \theta = 1 \cdot \frac{\pi}{8} = \frac{\pi}{8} = 0.392699$

God bless...I hope the explanation is useful.