# A circle has a center at (7 ,6 ) and passes through (2 ,1 ). What is the length of an arc covering pi/12 radians on the circle?

Using distance formula, solve for the distance between (7,6) and (2,1). That would be sqrt((7-2)^2 +(6-1)^2 equal to $5 \sqrt{2}$ units. Since, arc length $S = r \theta$ where r is the radius and $\theta$ is in radians. Multiplying: $5 \sqrt{2} \times \frac{\pi}{12} = 1.8512 u n i t s$