A circle has the equation #x^2+y^2=16#. How do you find the center ,radius and the intercepts?
1 Answer
Mar 5, 2016
centre (0,0) , r=4 , (±4,0), (0,±4)
Explanation:
The standard form of the equation of a circle is
#(x - a )^2 + (y-b)^2 = r^2 # where (a,b) are the coords of the centre and r , the radius.
#x^2 + y^2 = 16 " is in this form "# with a = b = 0 and r = 4
hence this circle has centre at the origin (0,0) and radius 4
The intercepts will therefore be (± 4,0) and (0, ± 4 )
