A circle is described by the equation #(x−12)^2+(y−32)^2=49#. What are the coordinates for the center of the circle and the length of the radius?

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Answer 1 · 2016-01-30T05:55:41

Center #(h, k)=(12,32)#
Radius #r= 7#

The radius - center form of the equation of the circle is given:

#(x-h)^2+(y-k)^2=r^2# where #(h, k)# the center
and #r# the radius of the Circle.

From the given: #(x-12)^2+(y-32)^2=49#

Also equivalent to #(x-12)^2+(y-32)^2=7^2#

clearly by inspection , center #(h, k)=(12,32)#

and Radius #r= 7#

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