# How do you find the critical points for #(9x^2)/25 + (4y^2)/25 = 1#?

##### 1 Answer

Oct 27, 2016

#### Answer:

Critical points are

#### Explanation:

A critical point of a differentiable function is any point on the curve in its domain, where its derivative is

For

i.e.

which is

Further,

Hence, critical points are

graph{(9x^2)/25+(4y^2)/25=1 [-5, 5, -2.5, 2.5]}