# A coin is flipped 12 times. What is the probability of getting exactly 8 heads?

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The number of possible sequences of heads and tails in

#2^12 = 4096#

The number of ways that such a sequence could contain exactly

#((12),(8)) = (12!)/((8!)(4!)) = (12xx11xx10xx9)/(4xx3xx2xx1) = 495#

So the probability of exactly

#495/4096#

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Probability of getting exactly 8 heads in tossing a coin 12 times is

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If a coin is tossed 12 times, the maximum probability of getting heads is 12.

But, 12 coin tosses leads to

Let E be an event of getting heads in tossing the coin and S be the sample space of maximum possibilities of getting heads. Then probability of the event E can be defined as,

NOTE: To know more about probability, please check into :

http://www.careerbless.com/aptitude/qa/probability_imp.php.

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