# A compound has the empirical formula of "CH"_2"O" and a molar mass of 60 g/mole. What is the molecular formula?

Apr 3, 2018

${\text{C"_2"H"_4"O}}_{2}$
Empirical formula $\text{= CH"_2"O}$
Empirical formula mass $\text{= 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol}$
$\text{Molecular formula mass"/"Empirical formula mass" = "60 g/mol"/"30 g/mol} = 2$
Molecular formula = 2 × "CH"_2"O" = "C"_2"H"_4"O"_2