# A container has a volume of 15 L and holds 9 mol of gas. If the container is compressed such that its new volume is 2 L, how many moles of gas must be released from the container to maintain a constant temperature and pressure?

Oct 13, 2017

$7.8 m o l$ og gas must be released.

#### Explanation:

Avogadrio's law says that for an ideal gas $V \setminus \propto n$ or $V = k n$, where:

• $V$ is the volume of the container (${m}^{3}$)
• $n$ is the number of moles of gas ($m o l$)

So, ${V}_{1} / {n}_{1} = {V}_{2} / {n}_{2}$

For this question we want to find out ${n}_{2}$ so by rearranging we get $\frac{{V}_{2} {n}_{1}}{V} _ 1$

$15 L = 0.015 {m}^{3}$
$2 L = 0.002 {m}^{3}$

$\frac{0.002 \cdot 9}{0.015} = 1.2 m o l$

$9 - 1.2 = 7.8 m o l$ of gas lost.