A container has a volume of $3 L$ $3 L$ and holds $16 m o l$ $16 mol$ of gas. If the container is expanded such that its new volume is $6 L$ $6 L$ , how many moles of gas must be injected into the container to maintain a constant temperature and pressure?

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Answer 1 · 2016-08-17T02:47:35

32 moles of gas must be injected into the container.

The answer can be calculated by using Avogadro's law:

$\frac{v_{1}}{n_{1}} = \frac{v_{2}}{n_{2}}$ $v_1/n_1 = v_2/n_2$

The number 1 represents the initial conditions and the number 2 represents the final conditions.

Identify your known and unknown variables:

$Knowns:$ $color(magenta)("Knowns:"$
$v_{1}$ $v_1$ = 3 L
$v_{2}$ $v_2$ = 6 L
$n_{1}$ $n_1$ = 16 mol

$Unknowns:$ $color(teal) ("Unknowns:"$
$n_{2}$ $n_2$

Rearrange the equation to solve for the final number of moles:

$n_{2} = \frac{v_{2} \times n_{1}}{v_{1}}$ $n_2=(v_2xxn_1)/v_1$

Plug in your given values to obtain the final number of moles:

$n_2=(6 cancelLxx16mol)/(3\cancel"L")$ = $32 mol$

A container has a volume of 3 L3L3 L and holds 16 mol16mol16 mol of gas. If the container is expanded such that its new volume is 6 L6L6 L, how many moles of gas must be injected into the container to maintain a constant temperature and pressure?