A container with a volume of #12 L# contains a gas with a temperature of #140^o C#. If the temperature of the gas changes to #490 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-05-25T15:17:11

The new volume is #=14.24L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=12L#

The initial temperature is #T_1=140+273=413K#

The final temperature is #T_2=490K#

The final volume is

#V_2=T_2/T_1*V_1#

#=490/413*12#

#=14.24L#