# A container with a volume of 12 L contains a gas with a temperature of 150^o C. If the temperature of the gas changes to 640 ^o K without any change in pressure, what must the container's new volume be?

Oct 24, 2016

New volume is $18.15$ $L$

#### Explanation:

We know that, $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

So here,${P}_{1} = {P}_{2}$ = constant

${T}_{1} = {150}^{\circ} C$ = $\left(150 + 273\right)$ $K$,
${T}_{2} = 640$ $K$

${V}_{1} = 12$ $L$, V_2=?

So,
${V}_{2} = \frac{12 \times 640}{423}$= $18.15$ $L$