A container with a volume of #12 L# contains a gas with a temperature of #240^o C#. If the temperature of the gas changes to #420 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-01-06T06:55:06

The new volume is #=9.82L#

Apply Charles'Law

#V_1/T_1=V_2/T_2# #"at constant pressure"#

The initial volume is #V_1=12L#

The initial temperature is #T_1=240+273=513K#

The final temperature is #T_2=420K#

The final volume is

#V_2=T_2/T_1*V_1=420/513*12=9.82L#