# A container with a volume of 15 L contains a gas with a temperature of 210^o K. If the temperature of the gas changes to 150 ^o K without any change in pressure, what must the container's new volume be?

May 26, 2016

${V}_{f} = 10.71 L$

#### Explanation:

${V}_{i} = 15 L \text{ initial volume of the gas}$
${T}_{i} = {210}^{o} K \text{ initial temperature of the gas}$

${T}_{f} = {150}^{o} K \text{ final temperature of the gas}$
V_f=?" final temperature of the gas"

${V}_{i} / {T}_{i} = {V}_{f} / {T}_{f}$

$\frac{15}{210} = {V}_{f} / 150$

${V}_{f} = \frac{150 \cdot 15}{210}$

${V}_{f} = 10.71 L$