A container with a volume of #15 L# contains a gas with a temperature of #280^o K#. If the temperature of the gas changes to #340 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-05-24T05:54:12

#"The final temperature of gas is 18.21 L"#

#v_i=15 L" Initial Volume of Gas"#
#T_i=280 " "^o K" Initial Temperature of Gas"#

#T_f=340" "^o K" Final Temperature of Gas"#
#V_f=? " Final Temperature of Gas"#

#V_i/T_i=V_f/T_f#

#15/280=V_f/340#

#V_f=(15*340)/280#

#V_f=18.21 L#