A container with a volume of #"16 L"# contains a gas with a temperature of #"180 K"#. If the temperature of the gas changes to #"360 K"# without any change in pressure, what must the container's new volume be?

1 Answer
Jan 11, 2017

Answer:

The final volume will be exactly #"32 L"#.

Explanation:

This is an example of Charles' law , which states that the volume of a given amount of a gas at constant pressure is directly proportional to the Kelvin temperature.

The equation to use is:

#V_1/T_1=V_2/T_2#, where #V# is volume and #T# is temperature in Kelvins.

Known
#V_1="16 L"#
#T_1="180 K"#
#T_2="360 K"#

Unknown
#V_2#

Solution
Rearrange the equation to isolate #V_2#. Insert the known values and solve.

#V_2=(V_1T_2)/T_1#

#V_2=(16"L"xx360cancel"K")/(180cancel"K")="32 L"#