Question

A container with a volume of `"16 L"` contains a gas with a temperature of `"180 K"`. If the temperature of the gas changes to `"360 K"` without any change in pressure, what must the container's new volume be?

Answer 1

The final volume will be exactly `"32 L"`.

Explanation:

This is an example of Charles' law , which states that the volume of a given amount of a gas at constant pressure is directly proportional to the Kelvin temperature.

The equation to use is:

`V_1/T_1=V_2/T_2`, where `V` is volume and `T` is temperature in Kelvins.

Known
`V_1="16 L"`
`T_1="180 K"`
`T_2="360 K"`

Unknown
`V_2`

Solution
Rearrange the equation to isolate `V_2`. Insert the known values and solve.

`V_2=(V_1T_2)/T_1`

`V_2=(16"L"xx360cancel"K")/(180cancel"K")="32 L"`