# A container with a volume of "16 L" contains a gas with a temperature of "180 K". If the temperature of the gas changes to "360 K" without any change in pressure, what must the container's new volume be?

Jan 11, 2017

The final volume will be exactly $\text{32 L}$.

#### Explanation:

This is an example of Charles' law , which states that the volume of a given amount of a gas at constant pressure is directly proportional to the Kelvin temperature.

The equation to use is:

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$, where $V$ is volume and $T$ is temperature in Kelvins.

Known
${V}_{1} = \text{16 L}$
${T}_{1} = \text{180 K}$
${T}_{2} = \text{360 K}$

Unknown
${V}_{2}$

Solution
Rearrange the equation to isolate ${V}_{2}$. Insert the known values and solve.

${V}_{2} = \frac{{V}_{1} {T}_{2}}{T} _ 1$

V_2=(16"L"xx360cancel"K")/(180cancel"K")="32 L"