A container with a volume of #16 L# contains a gas with a temperature of #320^o K#. If the temperature of the gas changes to #350 ^o K# without any change in pressure, what must the container's new volume be?

1 Answer
Dec 22, 2017

Answer:

#V=17.5"L"#

Explanation:

The ideal gas law gives:

#(P_1V_1)/T_1=(P_2V_2)/T_2#

Which for constant pressure becomes:

#V_1/T_1=V_2/T_2#

We can solve for #V_2#, the container's final volume:

#V_2=(V_1T_2)/T_1#

We are given that:

  • #V_1=16"L"#
  • #T_1=320"K"#
  • #T_2=350"K"#

Substituting these values into the equation above,

#V_2=(16*350)/(320)#

#=17.5"L"#

Or, #V_2~~18"L"# depending on how your teacher feels about significant figures...