# A container with a volume of 17 L contains a gas with a temperature of 290^o C. If the temperature of the gas changes to 580 ^o K without any change in pressure, what must the container's new volume be?

Apr 18, 2017

The new volume is $= 17.51 L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

Initial volume is ${V}_{1} = 17 L$

Initial temperature is ${T}_{1} = 290 + 273 = 563 K$

Final temperature is ${T}_{2} = 580 K$

Final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1}$

$= \frac{580}{563} \cdot 17 = 17.51 L$