A container with a volume of #18 L# contains a gas with a temperature of #270^o C#. If the temperature of the gas changes to #640 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-10-09T06:01:31

The new volume is #=21.22L#

Apply Charles' Law

#V_1/T_1=V_2/T_2#, #(P= #constant)

The initial volume is #V_1=18L#

The initial temperature is #T_1=(270+273)=543K#

The final temperature is #T_2=640K#

The final volume is

#V_2=T_2/T_1*V_1=640/543*18=21.22L#