A container with a volume of $18 L$ contains a gas with a temperature of $270^o C$ . If the temperature of the gas changes to $640 ^o K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-10-09T06:01:31

The new volume is $=21.22L$

Apply Charles' Law

$V_1/T_1=V_2/T_2$ , $(P=$ constant)

The initial volume is $V_1=18L$

The initial temperature is $T_1=(270+273)=543K$

The final temperature is $T_2=640K$

The final volume is

$V_2=T_2/T_1*V_1=640/543*18=21.22L$

A container with a volume of 18 L18 L contains a gas with a temperature of 270^o C270^o C. If the temperature of the gas changes to 640 ^o K640 ^o K without any change in pressure, what must the container's new volume be?