# A container with a volume of 25 L contains a gas with a temperature of 150^o K. If the temperature of the gas changes to 360 ^o K without any change in pressure, what must the container's new volume be?

May 19, 2017

$60. L$

#### Explanation:

We can use the temperature-volume relationship of gases illustrated by Charles's law:

$\frac{{V}_{1}}{{T}_{1}} = \frac{{V}_{2}}{{T}_{2}}$

Plug in known variables and solve for ${V}_{2}$:

${V}_{2} = \frac{\left(25 L\right) \left(360 K\right)}{150 K} = 60. L$