A container with a volume of #25 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

Question

905 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-19T00:04:33

#60. L#

We can use the temperature-volume relationship of gases illustrated by Charles's law:

#(V_1)/(T_1) = (V_2)/(T_2)#

Plug in known variables and solve for #V_2#:

#V_2 = ((25L)(360K))/(150K) = 60. L#