A container with a volume of $25 L$ contains a gas with a temperature of $150^o K$ . If the temperature of the gas changes to $360 ^o K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-05-19T00:04:33

$60. L$

We can use the temperature-volume relationship of gases illustrated by Charles's law:

$(V_1)/(T_1) = (V_2)/(T_2)$

Plug in known variables and solve for $V_2$ :

$V_2 = ((25L)(360K))/(150K) = 60. L$

A container with a volume of 25 L25 L contains a gas with a temperature of 150^o K150^o K. If the temperature of the gas changes to 360 ^o K360 ^o K without any change in pressure, what must the container's new volume be?