# A container with a volume of #32 L# contains a gas with a temperature of #480^o K#. If the temperature of the gas changes to #300 ^o K# without any change in pressure, what must the container's new volume be?

##### 1 Answer

#### Answer:

The new volume is

#### Explanation:

Let's identify our known and unknown variables.

The first volume we have is

We can obtain the answer using Charles' Law which shows that there is a direct relationship between *volume* and *temperature* as long as the pressure and number of moles **remain unchanged**.

The equation we use is

#V_1/T_1 = V_2/T_2#

where the numbers

Now we just rearrange the equation and plug the given values in:

#V_2 = (T_2 * V_1)/(T_1)#

#V_2 = (300cancel("K") * "32 L") / (480 cancel("K"))#

#V_2 = "20 L"#

When using the Kelvin scale, you do not put the degree symbol. You just write K.