A container with a volume of #4 L# contains a gas with a temperature of #720^o K#. If the temperature of the gas changes to #420^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-11-15T08:15:21

#"The final volume of gas is 2.33 Liters."#

#V_i:"initial volume "v_i=4L#

#T_i:"initial temperature "T_i=720 ^o K#

#T_f:"final temperature "T_f=420 ^o K#

#V_f:"final volume "V_f=?#

#V_i/T_i=V_f/T_f#

#4/720=V_f/420#

#V_f*720=4*420#

#V_f=(4*420)/(720)#

#V_f=1680/720=168/72#

#V_f=2.33L#