A container with a volume of #42 L# contains a gas with a temperature of #120^o K#. If the temperature of the gas changes to #75 ^o K# without any change in pressure, what must the container's new volume be?

Question

841 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-01T21:39:00

#V_2=26,25 L#

#"given data:"#
#V_1=42 L#
#T_1=120^o K#
#T_2=75^o K#
#V_2=?#

#"solution:"#
#V_1/T_1=V_2/T_2#

#42/120=V_2/75#

#V_2=(42*75)/120#

#V_2=26,25 L#