A container with a volume of #48 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #320 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-03-01T14:27:22

The new volume is #=102.4L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=48L#

#T_1=150K#

#T_2=320K#

#V_2=T_2/T_1*V_1#

#=320/150*48#

#=102.4L#