# A container with a volume of 48 L contains a gas with a temperature of 210^o K. If the temperature of the gas changes to 720 ^o K without any change in pressure, what must the container's new volume be?

Sep 7, 2017

#### Answer:

The new volume is $= 164.6 L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

Assuming that the pressure is constant

The initial volume is ${V}_{1} = 48 L$

The initial temperature is ${T}_{1} = 210 K$

The final temperature is ${T}_{2} = 720 K$

The final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1} = \frac{720}{210} \cdot 48$

$= 164.6 L$