A container with a volume of #48 L# contains a gas with a temperature of #210^o K#. If the temperature of the gas changes to #720 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-09-07T06:12:59

The new volume is #=164.6L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

Assuming that the pressure is constant

The initial volume is #V_1=48L#

The initial temperature is #T_1=210K#

The final temperature is #T_2=720K#

The final volume is

#V_2=T_2/T_1*V_1=720/210*48#

#=164.6L#