# A container with a volume of 48 L contains a gas with a temperature of 210^o K. If the temperature of the gas changes to 810 ^o K without any change in pressure, what must the container's new volume be?

Aug 26, 2016

185 Liters (at 810 K)

#### Explanation:

Let me write down a scientific fact first. When we use Kelvin temperature scale, we do not use degrees sign. This is a scientific rule.

Now the question is

$P \cdot V = n \cdot R \cdot T$

1st situation $48 \cdot V = n \cdot R \cdot 210$

n and R are constants therefore $V = \frac{210}{48}$

2nd situation 210/48=810/?

new volume will be ?=185 liters