A container with a volume of #5 L# contains a gas with a temperature of #360^o K#. If the temperature of the gas changes to #60^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-11-18T07:42:06

The new volume is #=0.83L#

Apply Charles' Law

#V_1/T_1=V_2/T_2#, at constant pressure

The initial volume is #V_1=5L#

The initial temperature is #T_1=360K#

The final temperature is #T_2=60K#

The final volume is

#V_2=T_2/T_1*V_1=60/360*5=5/6=0.83L#