A container with a volume of #6 L# contains a gas with a temperature of #100^o K#. If the temperature of the gas changes to #480 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-08T06:20:00

The volume is #=28.8L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=6L#

#T_1=100K#

#T_2=480K#

#V_2=T_2/T_1*V_1#

#=480/100*6#

#=28.8L#