Question

A container with a volume of `6 L` contains a gas with a temperature of `150^o K`. If the temperature of the gas changes to `570 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

Use Charles' Law: volume is directly proportional to absolute temperature at a fixed mass and constant pressure.

Explanation:

Charles' Law as stated above can be expressed as V =KT.
Volume is directly proportional to absolute temperature at a fixed mass (number of moles) and constant pressure. In this formula, K is just a proportionality constant. Absolute temperature means all temperatures must be expressed in Kelvin.

Another way to write this law is:

`V_1/T_1 = V_2/T_2`

Let `V_1 = 6L` and `T_1 =150K`
`V_2 = ?` and `T_2 = 570K`

`6/150 = V_2/570`

Cross multiply.
`6*570=150*V_2`
`V_2 = (6*570)/150 = 22.8L`