A container with a volume of 6 L contains a gas with a temperature of 150^o K. If the temperature of the gas changes to 570 ^o K without any change in pressure, what must the container's new volume be?

Sep 7, 2016

Use Charles' Law: volume is directly proportional to absolute temperature at a fixed mass and constant pressure.

Explanation:

Charles' Law as stated above can be expressed as V =KT.
Volume is directly proportional to absolute temperature at a fixed mass (number of moles) and constant pressure. In this formula, K is just a proportionality constant. Absolute temperature means all temperatures must be expressed in Kelvin.

Another way to write this law is:

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

Let ${V}_{1} = 6 L$ and ${T}_{1} = 150 K$
V_2 = ? and ${T}_{2} = 570 K$

$\frac{6}{150} = {V}_{2} / 570$

Cross multiply.
$6 \cdot 570 = 150 \cdot {V}_{2}$
${V}_{2} = \frac{6 \cdot 570}{150} = 22.8 L$